for a negative binomial distribution if nean and standard deviation are respectively 9and 6 then find thevalue of n
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Let n and p be parameters of binomial distribution.
Here,
Mean = np=9
Variance = npq=6
npnpq=96
q=32
p=1−32=31
Thus, n=27
Hence, binomial distribution is given by,
P(X=r)=27Cr(31)r(32)27−r, r=0,1,2,...,27
Comparing with given we get, k=27
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