Math, asked by anjali6740, 8 months ago

for a number to be a perfect cube, it must have prime factors in triplets.​

Answers

Answered by nazeefasif8
0

Answer:

mark as brainliest plz

Step-by-step explanation:

Here one factor 3 is not grouped in triplets. Therefore 81 must be divided by 3 to make it a perfect cube. Here one factor 2 does not appear in a 3's group. Therefore, 128 must be divided by 2 to make it a perfect cube.

Answered by Anonymous
2

Answer:

Factor in triplets is necessary

but not prime factor

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