Question

For a object
moving with uniform acceleration travelling 50 metres in 50 seconds and 70 metres in 7th second the initial velocities 5P metre per second where p

Answer 1

Answer:

Explanation:

GIVEN INITIAL VELOCITY= 5P

DISTANCE TRAVELLED IN NTH SECOND, Sn=U+A(n-0.5)

DISTANCE TRAVELLED IN  50 TH SECOND, S50=5P+A (50-0.5)

                                                                             50=5P+ 45.5 A..............(1)

DISTANCE TRAVELLED IN  7 TH SECOND, S7=5P+A(7-0.5)

                                                                         70=5P+6.5A...................(2)

(2)-(1),

20= - 39.5A

A= - 0.506 M/S²

USING THIS IN (1)

50= 5P-23.023

5P= 26.977

P= 5.39≈5.4 M/S.

HOPE THIS HELPS.