Question

For A.P 1,7,13,19 ……….. then find t18

(a) 100 (b) 103 (c) 102 (d) 105​

Answer 1

Answer:

Hi mate,

here is your answer

▪Algebra of the AP=dn(f-d)=6n+(1-6)=6n-5

t18=6×18-5=103

▪b)103

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Answer 2

Answer:

a18=??

here a=1

common difference d=6

n=18

hence

an=a+(n-1)d

=1+17*6

=1+102

=103