For A.P.3,9,15,21......find S10.
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Answered by
1
Answer:
Sn=n/2(2a+(n-1)d)
A=3,d=9-3 =6
S10=10/2(2(3)+(10-1)*6)
= 5*(6+9*6)
=5*+(54 +6)
=5*60
=300
S10=300
Answered by
0
Answer is 300
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