Math, asked by namratariva7510, 1 year ago

For A.P.3,9,15,21......find S10.

Answers

Answered by akssharma335588
1

Answer:

Sn=n/2(2a+(n-1)d)

A=3,d=9-3 =6

S10=10/2(2(3)+(10-1)*6)

= 5*(6+9*6)

=5*+(54 +6)

=5*60

=300

S10=300

Answered by akshatbhon765
0

Answer is 300

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