Question

For A.P. a= 5, d = 7, find t11​

Answer 1

Given :

• For A.P. a= 5 and d = 7

To find :

• 11th term i.e t11

Formula used :

$tn = a + (n - 1)d$

Where :

• a = first term

• n = number of terms

• d = common difference

• tn = nth term

Solution :

To find 11th term i.e t11 we will use the following formula :-

$tn = a + (n - 1)d$

Put :-

• a = 5

• n = 11

• d = 7

• tn = t11

$\implies \: t11 = 5+ (11 - 1)7$

$\implies \: t11 = 5+(10 \times 7)$

$\implies \: t11 = 5+70$

$\implies \: t11 = 75$

Answer :

11th term or t11 = 75

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$\large\bf\red{Learn\:More}$

1. Tn = a+(n-1)d

2. Sn = n/2[2a+(n-1)d]

3. Sn = n/2(a+l)

Where :-

• a = first term
• n = number of terms

• d = common difference

• tn = nth term

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