Question

for a particle moving along x axis the displacement time equation is x=t^3+12t+20 find the position and velocity of the particle at t =0

Answer 1

Hi friend here is your answer,

x=t^3+12t+20

dx=3t^2+12

putting, t=0

dx=0+12=12

And for velocity, v=6t (we know rate of change of displacement is velocity so just differentiate it w.r.t. t)

So, at t=0

v=0 m/s