Question

For a particle moving in a straight line the position of the particle at time (t) is given by x= t^3- 6t^2+3t +7 what is the velocity of the particle with acceleration is 0

Answer 1

differentite it with respect to time

velocity = dx/dt = 3t² - 12t + 3

acceleration = 6t -12 = 0

so t= 2


now velocity at 2 second is -9 m/s