Question

for a particle moving in circumference of a circle of fixed radius with constant speed dimension of phase space is

Answer 1

Answer:

For a 2D moving in a plane as in case of a circular motion, we have two degrees of freedom for the q i.e. for x – y plane, q1 = x and q2 = y, and two degrees of freedom for the velocity given by ux and vy and thus px and py.

⇒ dimension of phase space = 2 + 2 = 4.

The correct answer is: 4

Explanation:

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