Question

For a particle of 5 kg in one
dimensional motion, the position -
time graph is shown. What is the
impulse at t = Os and t = 4s?
(1 Point)
4
B
0​

Answer 1

Answer:

I am not fake but I am broken

Answer 2

Extra Question:-

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In the figure, AO = OD and OB = OC. Then

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In△AOD&△BCO

=>OD=OC (given)

OA=OB(given)

∠AOD=∠COB (vertically opposite)

=>△AOD≅△BOC

∠OAD=∠OBC(angles corresponding to congruent sides)

[∵ AD & BC make equal angles with the same line AB]

HenceAD∣∣BC