Question

For a particle of 5 kg rotated in horizontal circle of radius 5m. Find maximum angular velocity. If string can bear a maximum tension of 400N.

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Answer 1

Given info : For a particle of 5 kg rotated in horizontal circle of radius 5m.

To find : The maximum angular velocity if the string can bear a maximum tension of 400 N.

solution : maximum tension acts as centripetal force of the circular motion.

at equilibrium,

maximum tension = centripetal force

⇒400 N = mv²/r

we know for circular motion, v = ωr

⇒400N = m(ωr)²/r = mω²r

⇒400N = 5kg × ω² × 5 m

⇒16 = ω²

⇒ω = 4 rad/s

Therefore the maximum angular velocity is 4 rad/s.

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