for a particle v-x graph is given find acceleration at x = 3 m
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3
Answer:
here,
slope of line passing through (2,10)and (4,20) is
(20-10)/(4-2)
=5=dv/dx
equation of line passing through (2,10) is given by
v-10=5(x-2)
v=5x
when x=3
v=15m/s
acceleration is given by
a=v*dv/dx
=15*5
=75m/s²
Answered by
3
for v-t graph
Explanation:
acceleration from 2 to 4 second is same i.e 5
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