Math, asked by Anonymous, 6 months ago

For a particular frequency distribution table, the class size is 25 and the first class interval (continuous) is 200-225
a. Write the third class interval.
b. Write the class mark of the fourth class interval.
c. Write the difference between the upper limit of the second class interval and lower limit of the fourth class interval.

Answers

Answered by sonuvuce
1

a) The third class interval is 250 - 275

b) The class mark of fourth class interval is 287.5

c) The difference between the upper limit of the second class interval and lower limit of the fourth class interval is 25

Step-by-step explanation:

Given that

Class size of a frequency distribution = 25

Class interval = 200 - 225

Therefore,

Second class interval will be  225 - 250

Third class interval will be 250 - 275

Fourth class interval will be 275 - 300

The class mark of fourth class interval will be

=\frac{275+300}{2}

=287.5

Difference between upper limit of second class interval and lower limit of fourth class interval

=275-250

=25

Hope this answer is helpful.

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Answered by pulakmath007
19

\displaystyle\huge\red{\underline{\underline{Solution}}}

DEFINITION TO BE MEMORISED

CLASS SIZE

Class size = Upper limit - Lower limit of the class

CLASS MARK

The mid value of the class is called Class mark

GIVEN

For a particular frequency distribution table, the class size is 25 and the first class interval (continuous) is 200-225

TO DETERMINE

  • The third class interval

  • The class mark of the fourth class interval

  • The difference between the upper limit of the second class interval and lower limit of the fourth class interval

CALCULATION

Class size = 25

The first class interval (continuous) = 200-225

So first four classes are

  • FIRST CLASS = 200 - 225

  • SECOND CLASS = 225 - 250

  • THIRD CLASS = 250 - 275

  • FOURTH CLASS = 275 - 300

ANSWER TO QUESTION 1

The third class interval = 250 - 275

ANSWER TO QUESTION 2

The class mark of the fourth class interval

= The mid value of the class

  \sf{\displaystyle \:  =  \frac{275 + 300}{2} }

  \sf{\displaystyle \:  = \: 287.5}

ANSWER TO QUESTION 3

SECOND CLASS = 225 - 250

FOURTH CLASS = 275 - 300

Upper limit of the second class interval

= 250

Lower limit of the fourth class interval

= 275

So The difference between the upper limit of the second class interval and lower limit of the fourth class interval

= 275 - 250

= 25

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