Question

For a particular reversible reaction at temperature T, ∆H and
∆S were found to be both +ve. If Tₑ is the temperature at
equilibrium, the reaction would be spontaneous when
(a) Tₑ > T (b) T > Tₑ
(c) Tₑ is 5 times T (d) T = Tₑ

Answer 1

The reaction would be spontaneous when T>Te.

Option (B) is correct.

Explanation:

For a particular reversible reaction at T temperature

ΔG = ΔH − T.ΔS

When ΔH, S is positive

ΔG = +ΔH − T.( + ΔS)

For spontaneous process ΔG must be negative, it is possible only at high  temperature.

That mean T>Te

Thus the reaction would be spontaneous when T>Te.

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