Question

for a party 7 guest are invited by a husband and this wife. they sit in a row for dinner. the probability that the husband and his wife sit together , is

Answer 1

Husband and wife invited 7 quest 
So the whole number of  participant in the party =1( Including husband and wife+ 7 (Guest) = 8
Thus, the number of ways in a row of dinner  of arranging the participant/members = 8
The question is actually mentioning that husband and wife sit together so that make both together as  one (1)
Here the total guest is = 7 
So there number of ways of arranging will be = 7
On counting the husband and wife they will also be arranged in 2 ways.
Thus, total number of favorable ways to sit  will equal= 2 *7.
So the,probability will be = number of favorable ways /total number of possible ways
Put the value simply.
Probabiliy = 2 * 7/8 = 2/8  = 1/4
So the answer will be 1/4

Answer 2

Answer:

the answer is 1\4.

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