Question

For a point charge the graph between electric field versus distance is given by

Answer 1

Graph of Electric Field vs Distance:

• Let's assume that a point charge q is placed at the origin (0,0) of a coordinate system.

• The general expression of field intensity with respect to distance is :

$\boxed{ \bf E = \dfrac{q}{4\pi \epsilon_{0}( {r}^{2} ) } }$

• 'q' is charge , 'r' is the distance , $1/4\pi\epsilon_{0}$ is Coulomb's Constant.

• Since q is constant, we can say:

$\boxed{ \bf E \propto \dfrac{1}{{r}^{2} } }$

Hence, the graph will have a hyperbolic shape.