For a Poisson process with arrival rate 1 = 20 customers per hour, the expected number of
arrivals in the first 5 minutes of a hour is
(a) 4/3
(b) 5/3
(c) 2/3
(d) 4
O A. (a)
O B. (b)
O C. (c)
O D. (d)
Answers
Answered by
1
Answer:
B(b)
Step-by-step explanation:
1 hour = 20 customers
divide 1 hour by 5 minutes
60÷ 5 = 12
now divide the customers arrival rate per hour by 12
20÷ 12 = 10/6 = 5/3
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