for a polynomial p(x)=2x^3+5x^2-9 find alpha+beta+ gamma, alpha×beta+beta× gamma +gamma×alpha, alpha×gamma×beta
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Step-by-step explanation:
Given :-
The Cubic Polynomial P(x) = 2x³+5x²-9
To find :-
Find the values of the following :
i) α+β+ γ
ii) α β + β γ + α γ
iii) α β γ
Solution :-
Given that
The Cubic Polynomial P(x) = 2x³+5x²-9
It can be written as
P(x) = 2x³+5x²+0x-9
On comparing this with the standard Cubic Polynomial ax³+bx²+cx+d then
a = 2
b = 5
c = 0
d = -9
If α, β, γ are the zeroes of the given Polynomial then
I) Sum of the Zeroes = -b/a
=> α+ β+ γ = -5/2
ii) Sum of the product of the two zeroes taken at a time = c/a
=> α β + β γ + α γ = 0/2 = 0
iii) Product of the zeroes = -d/a
=> α β γ = -(-9)/2
=> α β γ = 9/2
Answer :-
I) α+ β+ γ = -5/2
ii)α β + β γ + α γ = 0
iii)α β γ = 9/2
Used formulae:-
- The standard Cubic Polynomial is ax³+bx²+cx+d
- Sum of the Zeroes = -b/a
- Sum of the product of the two zeroes taken at a time = c/a
- Product of the zeroes = -d/a
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