Question

For a prism having angle of prism 90° and angle of minimum deviation is 30° , then the refractive index of the prism is

Answer 1

Answer:

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Explanation:

The smallest angle through which light is bent by an optical element or system. In a prism, the angle of deviation is a minimum if the incident and exiting rays form equal angles with the prism faces. The angle is important relative to prism spectroscopes because it can be easily determined.

How do you find the angle of a prism when the refractive index is given?

Angle of minimum deviation for a prism of refractive index 1.5, is equal to the angle of the prism. Then the angle of the prism is : (Given cos41∘=0

Answer 2

Given ,

• Angle of prism (A) = 90°
• Angle of minimum deviation $\sf (δ_m)$ = 30

We know that ,

The refractive index of a prism in terms of angle of prism and angle of minimum deviation is given by

$\boxed{ \sf{n = \frac{ \sin( \frac{A + δ_m}{2} ) }{ \sin( \frac{A}{2} ) }} }$

Thus ,

n = Sin(120/2) ÷ Sin(45)

n = Sin(60) ÷ Sin (45)

n = √3/2 ÷ 1/√2

n = √6/2

∴ The refractive index of prism is √6/2