Question

for a projectile motion, drive expressions for its time of flight , maximum height and range .mention the special case
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Answer 1

sry mate , i had written all these topics in my notes but now i don't have them.

Answer 2

Step-by-step explanation:

As the body starts from X- Axis and ends it's journey on X-Axis. let theta be x

Displacement along X-Axis (Sy) =

Sy= uyt+1/2at^2

0= usinx + 1/2(-g) t^2

usinx=1/2(g)t^2

T = 2usinx/g

Therefore the equation for time of flight is (T) = 2usinx/g

velocity along Y-Axis = 0

vy=0

v^2-u^2=2aS

0-(usinx)^2= 2(-g)H

u^2sin^2x= 2gH

H=u^2sin^2x/2g

Therefore the equation for maximum height is H = u^2sin^2x/2g