Question

for a projectile square of range is 48 times of square of maximum height obtained find the angle of projection

Answer 1

given r^2 =48h^2
[u^2sin2theta/g]^2= 48[u^2sin^2theta/2g]^2
solving we get....
tan theta=1/root3
which is ....
theta=30

Answer 2

for a projectile square of range is 48 times of square of maximum height obtained find the angle of projection

Answer:

b) 30°