Physics, asked by shreyamathur4376, 11 months ago

.For a projectile the ratio of max. height reached to the square of time of flight is _____

Answers

Answered by aayushg1713
0

Time of flight = 2u sin(thetha) /g

Square of time = 4u^2 sin^2(thetha)/g^2

H max = u^2 sin^2(thetha)/2g

Ratio of h max and t^2 = g/8

Answered by 3524
1

Answer:5:4

Explanation:write formulas for hmax:time of flight

U^2sin2theta/g=2usintheta\f (2^2)

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Ans ?:4

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