.For a projectile the ratio of max. height reached to the square of time of flight is _____
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Time of flight = 2u sin(thetha) /g
Square of time = 4u^2 sin^2(thetha)/g^2
H max = u^2 sin^2(thetha)/2g
Ratio of h max and t^2 = g/8
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Answer:5:4
Explanation:write formulas for hmax:time of flight
U^2sin2theta/g=2usintheta\f (2^2)
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Ans ?:4
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