Question

for a projectile the ratio of maximum height reached to the square of flight time is(g=10m/s)

Answer 1

Answer:

5/4

Explanation:

Given :

H=U²Sin²θ/2g

T=2Usinθ/g

now if we take the ratio of maximum height reached to the square of flight time:

H/T²=U²Sin²θ/2g/4U²sin²θ/g²

=g/8

If we take g=10 m/s² then

H/T²=10/8=5/4

hope it helps.......