Question

For a projectile, the ratio of maximum height reached to the square of flight time is

Answer 1

Given :
H=U²Sin²θ/2g
T=2Usinθ/g
now if we take the ratio of maximum height reached to the square of flight time:
H/T²=U²Sin²θ/2g/4U²sin²θ/g²
=g/8
If we take g=10 m/s² then
H/T²=10/8=5/4

Answer 2

Answer:

5:4

Explanation:

H/T^2