Question

For a projectile the ration of maxmium height reached to the square of flight time is ( g = 10m/s2​

Answer 1

Answer:

5 / 4

Explanation:

1. max height of a projectile=   $u^{2}$ $sin^{2}$Ф / 2 g
2. time of flight= 2u sinФ / g

$t^{2}$ = 4 u² sin² Ф / g²

ratio = h / t²

        = u² sin²Ф / 2 g × g² / 4u² sin²Ф

        = g / 8

        = 10 / 8

        = 5 / 4