For a quadratic equation ax^2+bx+c=0, if discriminant is equal to zero,then where will ists graph touch the x-axis?
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It will touch the x-axis at x = -b/2a.
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Heya,
By quadratic formula :
x = {-b(+/-)underroot (b^2 - 4ac)} / 2a
When discriminant (i.e.,b^2-4ac) = 0
Then, x = -b/2a
Hence , the graph of y= p (x) or we can say that the graph of this equation will touch the x-axis at the point (-b/2 a, 0).
Note : The point/points at which the graph of y = p (x) touches the x-axis is/are a zero/root/solution of p (x).
Also, the zeroes of a polynomial ax^2+bx+c and the roots of the equation ax^2 + bx + c = 0 are the same.
Hope this helps. . . . . if it really helped, then please mark it as the BRAINLIEST and please say a thanks.
Thanks.
By quadratic formula :
x = {-b(+/-)underroot (b^2 - 4ac)} / 2a
When discriminant (i.e.,b^2-4ac) = 0
Then, x = -b/2a
Hence , the graph of y= p (x) or we can say that the graph of this equation will touch the x-axis at the point (-b/2 a, 0).
Note : The point/points at which the graph of y = p (x) touches the x-axis is/are a zero/root/solution of p (x).
Also, the zeroes of a polynomial ax^2+bx+c and the roots of the equation ax^2 + bx + c = 0 are the same.
Hope this helps. . . . . if it really helped, then please mark it as the BRAINLIEST and please say a thanks.
Thanks.
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