Question

For a quadratic equation sum of the roots is equal to product of roots. If the value of discriminate is zero then form and solve the equation.​

Answer 1

Step-by-step explanation:

let equation be x square+Bx+C=0 and let a and b be its roots.

then, according to question,

a+b=ab

and, B=(a+b)

and, C=ab

since discriminant is equal to zero, this

B square-4×1×C=0(as, We have taken A=0)

(a+b) square-4ab=0

ab(ab+1) =0

ab=0 or ab+1=0

ab=0 or ab=-1

Answer 2

Step-by-step explanation:

quadratic formulae = (-b-✓b^2-4ac)/2a=alpha, (-b+✓b^2-4ac)/2a=beeta

d=0

therefore, alpha=b/2a

beeta=-b/2a

equating product and sum we get

-b^2/4a=0

therefore

-b=2a

it means that the polynomial would be

x^2-2x+-y(any constant). (1)

quadratic polynomial making formula when product and sum are given of zeroes is

k(x^2-( sum)x+product).

let sum and product be a

hence

k(x^2-ax+a). (2)

comparing(1),(2)we get the polynomial as x^2-2x+2 ans

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