Chemistry, asked by apparisridevi1954, 9 months ago

For a quantum number n=3, the total possible values of magnetic quantum number will be?
(A) 5​

Answers

Answered by shrutibhardwaj0708
0

Answer:

The three quantum numbers (n, l, and m) that describe an orbital are integers: 0, 1, 2, 3, and so on. The principal quantum number (n) cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on. The angular quantum number (l) can be any integer between 0 and n - 1.

Similar questions