Question

For a raction NH4COONH2(s)⇌2NH3(g)+CO2(g), the equilibrium pressure is 3 atm. What is the

value of Kp for the reaction ​

Answer 1

Answer:

NH

4

COONH

2

(S)→2NH

3

(g)+CO

2

(g)

When temperature and volume are constant and the number of moles of a gas is proportional to its partial pressure

For two moles of NH

3

→ partial pressure =2p

For one mole of CO

2

→ partial pressure =p

Hence the total pressure =2p+p=3 (since p=1atm)

K

p

=(2p)

2

(p)=4p

3

=4(1)

3

=4

Answer 2

NH4COONH2(S)= 2NH3 (g) +CO2 (g)

When temperature and volume are constant and the number of moles of a gas is proportional to its partial pressure

For two moles of NNH → partial pressure =2p

For one mole of CO 2 → partial pressure =p

Hence the total pressure =2p+p=3

(since p=1atm)

Kp =(2p) 2 (p)=4p 3

=4(1) ³ =4

hopefully it will work ☺️☺️☺️