Question

For a radiation of 600 MHZ passing through air the wave number per 1 m length is

Answer 1

Answer:

v=1/λ

where k is the wave number

to find λ , we can use the eqn c=f*λ

therefore;

c/f=1/λ

3×10∧8/6×10∧8=1/λ

λ=2

then;

v=1/λ

v=1/2

v=0.5

Explanation:

Answer 2

The wave number is 2.

Explanation:

Given that,

Frequency of radiation, $f=600\ MHz=600\times 10^6\ Hz=6\times 10^8\ Hz$

We need to find the number of waves passing through air. We know that the radiation move with the speed of light such that,

$c=f\lambda\\\\\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6\times 10^8}\\\\\lambda=0.5\ m$

The number of waves in given wavelength is N. So,

$N=\dfrac{l}{\lambda}\\\\N=\dfrac{1}{0.5}\\\\N=2$

So, the wave number is 2.

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