For a reaction () - 2B(g), the value of AU and AS are 2 kJ/mole and 20 J/K/mole. Then, the AG (kJ/mol) of the reaction approximately is (T = 300 K)
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Answer:
ΔH
1
=ΔG
o
+TΔS
o
=20+200(−20)=−3980KJ
ΔH
o
=ΔE+C
p
ΔT
ΔE=ΔH
1
ΔH
o
=−3980+20(400−200)=−3980+4000=20kJ/mole
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