Question

For a reaction 2n2o5give 4no2+o2, Initial concentration of n2o5 is 7.2mol and after 20 min not is 2.4 mol then what will be the rate of decomposition of n2o5 in mol

Answer 1

The rate of decomposition of N₂O₅ is 0.06 mol L⁻¹ min⁻¹

Given-

• Initial concentration of N₂O₅ = 7.2 mol
• After 20 min concentration of NO₂ = 2.4 mol / L

For the first order reaction-

kt = ln A₀/At

where k is the rate constant, A₀ is the initial concentration and At is the concentration at time t.

By substituting the values we get

k × 20 = 2.303 log (7.2/2.4)

k = 0.06 mol L⁻¹ min⁻¹