Question

For a reaction A + 2 B  C, the amount of C

formed by starting the reaction with 5 moles of

A and 8 moles of B is

(1) 5 moles (2) 8 moles

(3) 16 moles (4) 4 moles

Answer 1

hi here is your answer miss,

A= 5 moles, i.e. 5/1=5

B=8 moles, i.e. 8/2=4

=> B is the limiting reagent.

We should also keep in mind that the product will be produced only until the limiting reagent is present, i.e., the amount of product formed is governed by the limiting reagent.

Therefore, amount of C produced is equal to 1 unit(as calculated above) that is equal to 4 moles.

HOPE IT HELPED

PLEASE MARK BRAINLIEST

BE BRANILY!!!

Answer 2

Answer:

sry mate....................................