Question

For a reaction,
A+B -- 2C+2D,Kp=1.2×10^3 kPa at 450k. Calculate the value of Kc in mol/l.

Answer 1

Answer:

The value of Kc will be 0.085 mol/L

Explanation:

The relation between Kp and Kc is given as :

Kp = Kc(RT)^Δn

=> Kc = Kp/(RT)^Δn

Where

R = universal gas constant = 8.314

T = temperature in kelvin = 450

Δn = number of mole change = (2+2) - (1+1) = 2

Kp = 1.2 x 10³ kPa = 1.2 x 10⁶ Pa

Putting these values in the above equation we get,

Kc = 1.2 x 10⁶/(8.314x450)²

= 1.2 x 10⁶/1.4 x 10⁷

= 0.085 mol/L

Hence the value of Kc will be 0.085 mol/L