Question

For a reaction A +B-->P, the rate is given by-
rate= [A][B]^2
i) How is the rate of reaction affected if the concentration of B is doubled.

ii)What is the overall order of reaction if A is present in large excess.​

Answer 1

i)Since rate is proportional to [B]^2 ...therefore, on doubling the concentration of a rate becomes 4 TIMES.

ii) if A is taken in excess, overall rate of reaction would become independent of concentration of A. Hence rate will be proportional to only [B]^2.

Therefore, order of reaction becomes 2.

Hope it helps ya:)