Question

For a reaction, activation energy E = 0 and the
rate constant at 200 K is 1.6 x 106 s-1. The rate
constant at 400 K will be
[Given that gas constant, R = 8.314 J K-1 mol-']
[NEET-2019 (Odisha)]
(1) 3.2 x 106 s-1
(2) 3.2 x 104 s-1
(3) 1.6 106 s-1
(4) 1.6 x 103 s-1​

Answer 1

${\huge{\boxed{\tt{\color {red}{❥ ᴀɴsᴡᴇʀ}}}}}$

3.) is a ✔ right Answer. 1.6×10s

hope this will help u

Answer 2

Ea =0

∴log k 1 /k2 =1

or

k 2 =k 1

=1.6×10 6 s −1

c will be the correct ans