Question

For a reaction at 47°C
deltaG = -12 Kcal and deltaH = 17.5 Kcal. Find out deltaS.​

Answer 1

Answer:

T=47+273=320 K

∆H=17.5 Kcal

∆G=-12Kcal

∆G =∆H-T∆S

-12000=17500-320∆S

∆S=92.18 cal

Explanation:

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