Question

For a reaction between A and B the order with respect to A is
2 and the order with respect to B is 3. The concentrations of
both A and B are doubled, the rate will increase by a factor
of: [NEET Kar. 2013]
(a) 10 (b) 12
(c) 16 (d) 32

Answer 1

The rate increases by a factor of 32.

Option (D is correct.

Explanation:

The expression for rate law for the above reaction is given by:

r = k [A]^2[B]^3

Where k denotes the rate constant.

Now when the concentration of both species are doubled, the new rate of the reaction is given by:

r′ = k[2A]^2[2B]^3  = 32 k[A] [B]

Diving the new rate by the original rate of the reaction, we get:

r′r=32

Thus the rate increases by a factor of 32.

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