Question

For a reaction between A and B the order with respect to A is 2 and the order with respect to B is 3. The concentrations of both A and B are doubled, the rate will increase by a factor of:
(a) 10
(b) 12
(c) 16
(d) 32

Answer 1

a-10 is the answer bbcoz total rate is like 5 times 2 so 10

Answer 2

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The expression for rate law for the above reaction is given by:

r=k[A]2[B]3

where k denotes the rate constant.

Now when the concentration of both species are doubled, the new rate of the reaction is given by:

r′=k[2A]2[2B]3=32k[A][B]

Diving the new rate by the original rate of the reaction, we get:

r′r=32

thus rate increases by a factor of 32.