For a reaction both enthalpy change and entropy change are positive . under what conditions the reaction will be spontaneous
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When the absolute temperature is greater than ΔH/ΔS
For a reaction to be considered spontaneous, Gibbs free energy must be negative.
The equation for Gibb's free energy is ΔG=ΔH−TΔS, where:
ΔH = enthalpy change (kJ mol−1)
T = absolute temperature (K)
ΔS = entropy change (J K−1)
So, here we have: ΔG=ΔH−TΔS
ΔG<0 for a reaction to be considered spontaneus.
So, we have: ΔH−TΔS<0
ΔH<TΔS
T>ΔHΔS
For a reaction to be considered spontaneous, Gibbs free energy must be negative.
The equation for Gibb's free energy is ΔG=ΔH−TΔS, where:
ΔH = enthalpy change (kJ mol−1)
T = absolute temperature (K)
ΔS = entropy change (J K−1)
So, here we have: ΔG=ΔH−TΔS
ΔG<0 for a reaction to be considered spontaneus.
So, we have: ΔH−TΔS<0
ΔH<TΔS
T>ΔHΔS
Answered by
0
Answer:
Let us consider the equation for gibbs free energy
ΔG=ΔH−TΔS
Where,
∆H is enthalpy change (KJmol−1 )
T is absolute temperature (K)
ΔS is entropy change (JK −1 )
For a reaction to be considered spontaneous ΔG<0
Therefore,
ΔH−TΔS<0
ΔH<TΔS
or
T>ΔHΔS
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