Question

For a reaction K, = 0.125 atm-2 Kc for given reaction at 127°C is (Take R = 0.08 atm L/mole-K)-
a) 128 M-2
b) 64 M-2
c) 32 M-2
d) 1/8 M-2​

Answer 1

Explanation:

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Class 11

>>Chemistry

>>Equilibrium

>>Homogeneous and Heterogeneous Equilibria

>>At 700 K, the equilibrium constant, Kp f

Question

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At 700K, the equilibrium constant, K

p

for the reaction 2SO

3

(g)⇌2SO

2

(g)+O

2

(g) is 1.80×10

−3

kpa.What is the numeriacal value in moles per litre of K

c

for this reaction at the same temperaure?

Medium

Solution

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Correct option is A)

Given: 2SO

3

⇌2SO

2

+O

2

1 atm=10

5

pa

Δn=n

products

−n

reactants

K

p

=1.8×10

−3

KPa=1.8Pa=1.8×10

−5

atm

T=700K

R=0.0821lit−atm

K

p

=K

c

(RT)

Δn

g

K

c

=

RT

K

p

K

c

=

700×0.0821

1.8×10

−5

=0.031×10

−5

=3.1×10

−7

molL

−1

Answer 2

Answer:

B

Explanation:

correct answer is option B

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