Chemistry, asked by kkumar9790pdju5o, 10 months ago

For a reaction, the rate constant is express
as.
k = A.e-40000/T
The energy of the activation is -
(A) 40000 cal (B) 88000 cal
C) 80000 cal (D) 8000 cal​

Answers

Answered by atulpatel64
0

Answer:

energy=40000 calorie

Explanation:

I hope my answer is correct

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