for a reaction∆u for the reaction is
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For the reaction, 2HI(g)→H
2 (g)+I 2 (g), ΔH is equal to ΔUΔH =ΔU +ΔnRT
For the reaction, 2HI(g)→H 2(g)+I 2 (g), Δn =1+1−2=0
Hence, ΔH =ΔU +(0)RTΔH =ΔU
Note: Δn is the difference between the number of moles of gaseous products and the number of moles of gaseous reactants.
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