Chemistry, asked by kunjshah06peqc0v, 1 year ago

For a reversible gaseous reaction N2 +3H2 → 2NH3 at equilibrium, if some moles of H, are replaced by same number of moles of T2 (T is tritium, isotope of H and assume isotopes do not have different chemical properties) without affecting other parameters, then:

(a) the sample of ammonia obtained after sometime will be radioactive.

(b) moles of N2 after the change will be different as compared to moles of N present before the change

(c) the value of Kp, or Kc will change

(d) the average molecular mass of new equilibrium will be same as that of old equilibrium


Sreekar273: If a reaction is at equlibrium then it should be reversible
kunjshah06peqc0v: Yeah it is reversible...so what?

Answers

Answered by Sreekar273
6

I think it is A - the sample of ammonia obtained after sometime will be radioactive,

Because Tritium is a radioactive isotope of the element hydrogen.


kunjshah06peqc0v: You're Right... But I was unaware of the reason... Thanks
Answered by anikasusanmathew
0

Answer:

a) the sample of ammonia obtained will be radioactive

Explanation:

Instead of NH3, either NH_{2} T or NHT_{2} is obtained.

Why?

Since Tritium is a radioactive isotope of hydrogen.

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