Question

For a reversible process at t =300k the volume is increased from v=1 l to v2 = 10 l calculate enthalpy if the process is isothermal

Answer 1

Hii dear,

# Answer- ΔH = ΔU = 0J

# Explanation-

We know that, for ideal gases, relationship between enthalpy(H) with internal energy(U) and PV can be written as-

ΔH = ΔU + PΔV

ΔH = ΔU + Δ(nRT)

But R and n are constant, hence

ΔH = ΔU + nRΔT

Since the process is isothermal, ΔT = 0.

Therefore-

ΔH = ΔU

However, for isothermal process, the change in internal energy, ΔU = 0.

Hence-

ΔH = ΔU = 0

Hence, change in enthalpy is zero.

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