For a reversible process at t =300k the volume is increased from v=1 l to v2 = 10 l calculate enthalpy if the process is isothermal
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# Answer- ΔH = ΔU = 0J
# Explanation-
We know that, for ideal gases, relationship between enthalpy(H) with internal energy(U) and PV can be written as-
ΔH = ΔU + PΔV
ΔH = ΔU + Δ(nRT)
But R and n are constant, hence
ΔH = ΔU + nRΔT
Since the process is isothermal, ΔT = 0.
Therefore-
ΔH = ΔU
However, for isothermal process, the change in internal energy, ΔU = 0.
Hence-
ΔH = ΔU = 0
Hence, change in enthalpy is zero.
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