For a reversible reaction A 2B, when [A]= [B] = 0.5 mol L–1 rate of forward reaction is 2 times the rate of backward reaction. Kc for the reaction is : 1) 1 2) 0.25 3) 0.125 4) .5
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Answer:
) 1
Explanation:
Rate of a reaction = Kf / Kb
Given Rf = 2Rb
Kf [A] = Kb [B]²
Rate of a reaction = 2 /0.5 =1
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Answer :-
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Explanation :-
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