Question

For a reversible reaction at 27°C, change in Gibbs
energy at standard state (AG°) is -690.9 R. If rate
constant of forward reaction is 4 * 10-3 unit then
value of Kb is [Kf and Kb have same unit , R is gas
constant]
(1) 4 x 10-4 unit (2) 4 x 10-3 unit
(3) 4 * 10-2 unit (4) 4 x 10-1 unit​

Answer 1

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Answer 2

Option A is the correct answer

Given:

For a reversible reaction at T = 27°C

Gibbs energy at standard state (AG°) = -690.9 R

constant of forward reaction Kf =  4 x 10^-3

Explanation:

The required formula for calculating constant of backward reaction,

ΔG = -RT X ln(Kf/Kb)

-690.9 R = R x 300 x ln (4 x 10^-3/Kb)

ln (4 x 10^-3/Kb) = 2.303

(4 x 10^-3/Kb) = $e^{2.303}$ = 10

Kb = 4 x 10^-4 unit

hence, the constant of backward reaction Kb is 4 * 10^-4