Question

for a reversible reaction taking place at 127 ° and 1 atm ∆° g is 23.5 for the forward reaction calculate the value of constant equilibrium​

Answer 1

Explanation:

G=G^O -RTLOGK

AT equilibrium G equals to zero

g^o=RTLOGK

23.5/0.0821×400 = log k

0.71559=logk

10^0.7559=k

k= 5.185 ( in atm and liter units)