Question

for a sample space omega ={ w1, w2, w3, w4} P(w1) = 1/8 = P(w2), P(W3)=K, P(w4)r 3/4
For what value of 'K' will this be a probability model

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Answer 1

Answer:

w1 = 1/8

w2 = ?

w3= k

w4= 3/4

ans. is = 0

Answer 2

Answer:

K=0

Step-by-step explanation:

We know that the probability of a sample space always sums upto 1

Given:

P(w1)=1/8=P(w2)

P(w3) = K

P(w4) = 3/4

To find 'K'

P(w1) + P(w2) + P(w3) + P(w4) = 1

$\frac{1}{8}+\frac{1}{8} + K + \frac{3}{4} =1$

$\frac{1}{4}+ K + \frac{3}{4} =1$

$K+\frac{1+3}{4}=1$

$K+1=1$

K = 0

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