Question

For a satellite moving in an orbit around the earth the ratio of kinetic energy to potential energy is

Answer 1

Answer:

k.e. of the satellite=1/2*m*v^2 

p.e. of satellite=-GmM/r (Formula for potential energy of a body placed near earth 

or for the earth-satellite system) 

Since the centrifugal force actin' on the satellite is provided by the gravitational force=

mv^2/r=GmM/r^2 

v^2=GM/r 

Therefore k.e.=GmM/2r 

Ratio becomes=-1/2=-0.5 

m-mass of satellite 

M-mass of earth 

r-distance of satellite from earth's centre 

v velocity of satellite 

Answer 2

Answer:

1 : 2

Explanation:

It is the answer of the above question .